Question

the dimensions of universal gravitional constant are​

Answer 1

Answer:

units of G = Nm² / kg²

dimensions = [MLT⁻²] [ L² ] [M⁻²]

                   = [ M⁻¹L³T⁻² ]

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Answer 2

We Know that,

$\bf\bold{F = \frac{GMm}{r^2}}$

Thus,

G= Fr²/Mm.............[1]

Now,

$\bf{Force \rightarrow \ Newton \rightarrow \ ML{T}^{-2}}$

$\bf{Mass \ \rightarrow \ M}$

$\bf{Radius \rightarrow \: Length \rightarrow\: L}$

Substituting the dimensions of the quantities,we obtain:

$\bf{G = \frac{MLT^{-2}L^2}{M^2}}$

$\Large\bold{\boxed{\boxed{G = \frac{MLT^{-2}L^2}{M^2} }}}$