Question

The dimentional formula of conductivity is.

(A) ML3T–3A–2 (B) M–1L–3T3A2 (C) ML2T–3A–2 (D) M–1L–2T3A2​

Answer 1

Answer:

conductivity  =  1/R = I/V

                       = I/V

                    V= W/Q    ( Q = charge ,   )

                    V =  ML²T⁻² / It        ....................q= it

                    V= ML²T⁻³I ⁻2

where I can express in ampere i.e. in A

so final answer is   ML²T⁻³A⁻²

option C is correct answer.  

Answer 2

Answer:

Explanation:

Resistance=potential

= [ ML^2T^-3A^-2] / [A]

=[ ML^2T^-3A^-2]

Now, Conductance = 1/Resistance

= 1/ [ML^2T^-3A^-2]

= [ M^-1L^-2T^3A^2]

S.I unit = Saimen