the dimentions of a room are 8m ,6m and5m. find the cost of distempering its four wall at the rate of ruppee 80 per square metre
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The surface area of cuboid is 2*(l*b)+(b*h)+(l*h).
=>2*(8*6)+(6*5)+(8*5)
= 2*(48+30+40)
=2*108
=216 sq.m
Now, the rate of distempering is ₹80 per sq.m
= 216/80
=27/10
=₹2.7
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=>2*(8*6)+(6*5)+(8*5)
= 2*(48+30+40)
=2*108
=216 sq.m
Now, the rate of distempering is ₹80 per sq.m
= 216/80
=27/10
=₹2.7
Please mark as brainliest if it helps you..
kittu49:
formula is wrong
Answered by
1
dimentions of a room are 8m, 6m, and 5m.
so that, l=8m, b=6m and h=5m
now, area of its four wall=2(l+b)*h
=2(8+6)*5
=2*14*5
=140m^2
hence, cost of distempering 1m^2=80 rupees
therefore, cost of distempering 140m^2=140*80
=11200 rupees Answer
plz mark me as brainliest if this answer is helpful.
so that, l=8m, b=6m and h=5m
now, area of its four wall=2(l+b)*h
=2(8+6)*5
=2*14*5
=140m^2
hence, cost of distempering 1m^2=80 rupees
therefore, cost of distempering 140m^2=140*80
=11200 rupees Answer
plz mark me as brainliest if this answer is helpful.
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