Question

The dining hall of a hotel is 12.5 m long, 9 m broad and 7 m high. It has two – doors 2.5m by 1.2m each and four windows 1.5 m by 1 m each. Find the cost of papering its wall at the rate of ₹ 3.50 per m^2.​

Answer 1

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Answer 2

Answer:

$\sf\pink{Total\: Cost = ₹1011.5}$

GIVEN :-

$\sf{Length\: of\: dinning \:room = 12.5 \:m}$

$\sf{Breadth \:of \:dinning \:room = 9\: m}$

$\sf{Height \:of \:Dinning \:room\: = 7\: m}$

$\sf{Four \:windows \:of\: 1.5 \:m \:by \:1 \:m}$

$\sf{Two\: doors \:of \:2.5\: m\: by \:1.2\: m}$

$\sf{Cost \:of\: 1\: m = ₹ 3.50 }$

TO FIND -:

$\sf{Total \:Cost \:of \:papering \:its \:wall }$

SOLUTION-:

So,

$\sf{Area \:of\: wall = 2h(l + b)}$

$\sf{Area \:of\: wall = 2 × 7(12.5 + 9)}$

$\sf{Area\: of \:wall = 14(21.5)}$

$\sf{Area\: of\: wall = 301 \:m²}$

Now,

$\sf{Area \:of \:two \:doors = 2( l × b)}$

$\sf{Area \:of \:two \:doors = 2(2.5 × 1.2)}$

$\sf{Area \:of \:two \:doors = 2(3)}$

$\sf{Area \:of\: two\: doors = 6 \:m²}$

Now,

$\sf{Area \:of\: 4 \:windows = 4(l × b)}$

$\sf{Area\: of \:4 \:windows = 4( 1.5 × 1)}$

$\sf{Area\: of\: 4 \:windows = 4(1.5)}$

$\sf{Area\: of \:4 \:windows = 6 \:m²}$

Now again,

(Total area of walls = Area of wall - Area of two doors - Area of 4 windows )

$\sf{Total \:area \:of \:walls = 301 - 6 - 6}$

$\sf{Total \:area = 289 \:m²}$

Therefore,

$\sf{Total \:Cost = 289 × 3.5}$

$\sf{Total \:Cost = ₹1011.5}$