Question

the dinomenator of a fraction is 1 more than twice it's numerator if numerator and dinomenator are both increased by 5 ,it becomes 3/5.Find the original fraction​

Answer 1

Step-by-step explanation:

Given :-

The dinominator of a fraction is 1 more than twice it's numerator if numerator and dinomenator are both increased by 5 ,it becomes 3/5.

To find :-

Find the original fraction ?

Solution :-

Let the numerator be X

The denominator = 1 more than the twice its numerator

=> (2X+1)

Then the fraction = Numerator/ Denominator

=> X/(2X+1) of

If the numerator and the denominator are increased by 5 it becomes 3/5

=> (X+5)/(2X+1+5) = 3/5

=> (X+5)/(2X+6) = 3/5

On applying cross multiplication then

=>3(2X+6) = 5(X+5)

=> 6X+18 = 5X+25

=> 6X-5X = 25-18

=> X = 7

Numerator = 7

Denominator = 2(7)+1= 14+1=15

Therefore, Fraction = 7/15

Answer:-

The original fraction for the given problem is 7/15

Check :-

Fraction = 7/15

Denominator = 2(7)+1

=> 2(Numerator)+1

The denominator is 1 more than the twice its numerator

and

If the numerator and the denominator are increased by 5 it becomes 3/5

=> (7+5)/(15+5)

=> 12/20

=> (3×4)/(5×4)

=>3/5

Verified the given relations in the given problem.