Math, asked by afzalqureshi9811, 8 months ago

the dinominator of the number has an irrational number
$1 \div \sqrt{2}$

Answers

Answered by Anonymous

16

Step-by-step explanation:

$\boxed{yes\: the\: denominator\: of\: the\: number\: is\: an\: irrational\: number\: because\: \sqrt{2}\: is\: an\: irrational\: number}$

Answered by deviv8390

10

Step-by-step explanation:

yes this is no of denominator

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