Physics, asked by manahilkhan391, 1 day ago

The diode shown in the circuit is a silicon diode. The potential difference between the points A and B will be A. 0.7v B. 0.6V D. 6 V C.OV​

Answers

Answered by anjalirehan04
15

In the given condition diode is in reverse biasing so it acts as open circuit. Hence potential difference between A and B is 6V.

option C 6 V is correct

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