The dioganal of a rhombus measure 16m and 30m. Find its petimeter
Answers
Answered by
1
hy
____
we know by the properties of rhombus
• its diagonal bisect each other
•its all sides are equal
•it diagonals bisect each other at 90°
now , using Pythagoras theorem
(hypotenuse)^2 = (base)^2 + (other side)^2
(AB)^2 = (OA)^2 + (OB)^2
(AB)^2 = (8)^2 + (15)^2
(AB)^2 = 64+225
AB = √289
AB = 17 m
perimeter of rhombus = 4 * side
= 4*17 m
= 68 m
for the figure refer to the attachment
hope helped
___________
____
we know by the properties of rhombus
• its diagonal bisect each other
•its all sides are equal
•it diagonals bisect each other at 90°
now , using Pythagoras theorem
(hypotenuse)^2 = (base)^2 + (other side)^2
(AB)^2 = (OA)^2 + (OB)^2
(AB)^2 = (8)^2 + (15)^2
(AB)^2 = 64+225
AB = √289
AB = 17 m
perimeter of rhombus = 4 * side
= 4*17 m
= 68 m
for the figure refer to the attachment
hope helped
___________
Attachments:
Similar questions