Question

The
diognal of a rombus measure 16 cm and 30 cm find its perimeter

Answer 1

hey mate ur ans

$area = 1/2(d1*d2)$

$area=1/2(16*30)$

$area=1/2*480$

$area=240cm^2$

now as diagonal is equal so one diagonal would be = 8and 8 cm or 16cm another would be 15 and 15 cm or 30 cm

let side be = a

now using Pythagoras

$8^2+15^2=a^2$

$64+225=a^2$

$289=a^2$

$root 289= a$

$17=a$

NOW IF a =17.

so perimeter

$4a$

$17*4$

$68$

perimeter= $68$