the diognals of a rhombus are of length 6 cm and 8 cm find the length of each side of the Rhombus
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Answer:
By pythagoras theorem, x^2=6^2+8^2
X^2= 36+64
X^2=100
X=10
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Step-by-step explanation:
side=√(1stdiagonal/2)^2+(2nd diagonal/2^2)
=√6/2)^2+(8/2)^2
√9+16
=√25
=5cm
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