Math, asked by lassi71, 9 months ago

The diognals of the quadrilateral are perpendicular
to each other, is such a quadrilateral always
a rhombus​

Answers

Answered by Anonymous
3

{\purple{\underline{\underline{\mathtt{Answer}}}}}

\bf\red{No}

\bf{It\:can\:either\:be\:a\:{\pink{rhombus\:}}or\:a{\pink{square}}}

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{\underline{\underline{\mathtt{\red{Rhombus}}}}}

\bf{Properties\:of\:a\:rhombus}

\mathtt{1.\:All\:sides\:are\:equal.}

\mathtt{2.\:Opposite\:sides\:are\:parallel.}

\mathtt{3.\:Diagonals\:intersect\:at\:90\degree}

\mathtt{4.Diagonals\:bisect\:each\:other.}

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___________________________

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{\underline{\underline{\mathtt{\red{Square}}}}}

\bf{Properties\:of\:a\:square}

\mathtt{1.\:All\:sides\:are\:equal.}

\mathtt{2.\:Opposite\:sides\:are\:parallel.}

\mathtt{3.\:Diagonals\:intersect\:at\:90\degree}

\mathtt{4.Diagonals\:bisect\:each\:other.}

\mathtt{5.\:All\:angles\:equal\:90\degree}

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\bf{Hence,}

\bf\blue{To\:distinguish \:between\:rhombus\:and\:square,\:angles\:are}

\bf\blue{necessary.}

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