Chemistry, asked by Sheroneashok5296, 1 year ago

The dipole moment HBr is 2.60×10-30 C m and the interatomic distance is 141 pm.What is the percentage ionic character of HBr.

Answers

Answered by arumairajppbnso8
0

μ = Q x d


= 1.6 x 10^-19 x 141 x 10^-12 C-m

= 22.56 x 10^-30 C-m


% ionic character = actual dipole x 100/theoretical dipole

= 2.6 x 100/22.56 = 11.53%

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