The dipole moment HBr is 2.60×10-30 C m and the interatomic distance is 141 pm.What is the percentage ionic character of HBr.
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μ = Q x d
= 1.6 x 10^-19 x 141 x 10^-12 C-m
= 22.56 x 10^-30 C-m
% ionic character = actual dipole x 100/theoretical dipole
= 2.6 x 100/22.56 = 11.53%
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