Question

The dipole moment of a dipole formed by a proton and an electron at a distance 1 nm is

Answer 1

use the formula p= q ×2a

then u will get
p =1.6×10*-19 × 10*-9
the answer is 1.6×10*-28

Answer 2

Dipole moment = 1.6 * 10⁻²⁸ C m

Explanation:

• Dipole moment is a quantity given as product of any change of the dipole and the distance between the charges (equal and opposite charges form a dipole and electron and proton are equal and opposite charges)
• It is represented by P
• It is a vector quantity

$Dipole moment = charge * distance$

=> P = q * 2a                

 ( where q= charge, 2a = distance between the charges)

charge on an electron = charge on proton = 1.6 * 10⁻¹⁹ C

=> P = 1.6 * 10⁻¹⁹ * 1* 10⁻⁹                     ( 1 n m= 10⁻⁹ m)

=> P = 1.6 * 10⁻²⁸ C m

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