Question

The dipole moment of HBr is $2.60 \times 10^{-30}$ C.m, and the inter atomic spacing is $1.41 \AA$ . What is the percent ionic character of HBr?

Answer 1

"A "dipole moment" is a measure of the "separation" of "two electric charges"" that are opposite. Moments of dipole are a "vector quantity". The magnitude corresponds to the charge multiplied by the distance between the chare and the direction from negative to positive charge.

Percentage ionic character is calculated as:

$\left( \frac {Observed\quad dipole\quad moment}{Calculated\quad dipole\quad moment}\right) \quad \times \quad 100$

Formula used to calculate dipole moment:

$\mu \quad =\quad e\quad \times \quad d\\ =\quad \frac {0.78\quad \times \quad {10}^{-8} }{ 1.41\quad \times {10}^{-8} }$

$\mu \quad =\quad 0.55\quad \times \quad {10}^{-10}$

$Percentage\quad of\quad ionic\quad character\quad =\quad \frac { 0.55\quad \times \quad {10}^{-10} }{ 4.8\quad \times \quad {10}^{-10} } \quad \times \quad 100\quad =\quad 11.7%$"

Answer 2

HEY MATE...

$\huge\red{Mew..\:=\: 0.55×10^-5}$