Question

The dipole moment of LiH is 1.964 x 10-29cm and the interatomic distance between Li and H in
this molecule is 1.596 Å. The percentage of ionic character in LiH is
(a) 75.0
(b) 76.8
(c) 79.8
(d) 100​

Answer 1

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The symbol of dipole moment is: μ

Now, μ= 1.964 x 10⁻²⁹distance d= 1.964Å

Now, charge δ= μ/d

= $\frac{1.964x10^-^2^9}{1.596x10^-^1^0}$ = 1.23 x 10⁻¹⁹

Ionic nature= charge on lithium/charge of electron

Now, $\frac{1.23x10^-^1^9}{1.6x10^-^1^9}$ x 100% = 76.825%

So, the answer is option (b)