The dipper in a ripple tank vibrates at a frequency of 4.0 Hz and the
resulting wave pattern is photographed. The distance between the two
crests shown is 20 cm. What is the speed of the wave?
Please give the solving also
Answers
Answered by
7
Solution: The frequency of the vibrating ripple = f = 4 Hz. The distance between the two crests is 20 cm.
Wavelength of the vibrating ripple = 2 x 20 = 40cm = 40/100 m = 0.4m.
Speed of the wave = frequency x wavelength = f x w = 4 x 0.4 = 1.6 m/s. Hence, the speed of wave = 1.6 m/s.
Answered by
3
Explanation:
The relationship between the speed (v) of a wave and its wavelength (λ) and frequency (f) is given as follows.
The equation is speed = wavelength*frequency. That is,
v=λ×f
In this case, the frequency is 4 Hz and the wavelength is 20 cm/5 as the distance of 5 crests and 5 troughs are given as 20 cm.
Therefore, v = 4 * 4 = 16 cm/s.
Hence, the speed of the wave is 16 cm/s.
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