Question

the direction of 20gf force is reversed. what is the magnitude of the resultant movement of the forces on the rod​

Answer 1

Explanation:

(ii) Moment of F1 = 20 gf x 6 cm F1 = 20 gf = 120 gf cm Moment of F2 = 12 gf x10 cm = 120 gfcm Since moment of F1 = moment of F2 → rod is in equilibrium (iii) If direction of 20gf is reverse, the resultant moment of force on rod is T = 120 gfcm + 120 gf cm = 240 gfcm.Read more on Sarthaks.com -/215060/which-of-the-two-forces-acting-on-the-rigid-rod-causes-clockwise-moment?show=215064#a215064