Physics, asked by Skumarsksk1823, 11 months ago

The discharge in (m3/s) for laminar flow through a pipe of diameter 0.04 m bearing a centerline velocity of 1.5 m/s is

Answers

Answered by gadakhsanket
1

Dear Student,

◆ Answer -

Discharge = 0.001884 m³/s

● Explaination -

# Given -

d = 0.04 m

v = 1.5 m/s

# Solution -

Cross sectional area of the pipe is -

A = πr²

A = πd²/4

A = 3.142 × 0.04² / 4

A = 3.14 × 4 × 10⁻⁴

A = 12.56×10⁻⁴ m²

Discharge for laminar flow is calculated by -

Discharge = A × v

Discharge = 12.56×10⁻⁴ × 1.5

Discharge = 0.001884 m³/s

Therefore, discharge for laminar flow is 0.001884 m³/s.

Thanks dear...

Similar questions