Question

the discriminant of the quadratic equation 2√2x²+10x+√2=0 is​
​

Answer 1

Given :

• quadratic equation: 2√2x²+10x+√2=0

To find :

• Discriminant of the given quadratic equation.

Formula used :

$\underline{ \boxed{ \sf \large \: d = {b}^{2} - 4ac}}$

Where :-

• d = discriminant
• b = coefficient of x
• a = coefficient of x²
• c = constant

Solution :

Given quadratic equation is :-

$\implies \sf2 \sqrt{2} {x}^{2} + 10x + \sqrt{2}$

Here :-

• a = 2√2
• b = 10
• c = √2

We have to find the value of discrimination.

$\sf \implies \: d ={ {b}^{2} - 4ac}$

$\sf \implies \: d ={ {(10)}^{2} -( 4 \times 2 \sqrt{2} \times \sqrt{2)} }$

$\sf \implies \: d ={ 100 -16 }$

$\sf \implies \: d =84$

Answer :

Discriminant of the given quadratic equation = 84