Question

The discriminant of the quadratic equation 2x2+4x-7=0 is
1. 72
2. 62
3. 210
4.71
5. -40

Answer 1

Step-by-step explanation:

discriminate= b²-4ac

=4²-4(2)(-7)

=16+56=72

Answer 2

Answer:

The value of discriminant of the quadratic equation is 72 and option 1 is correct.

Step-by-step explanation:

As per the data given in the questions

We have to calculate the value of discriminant of the quadratic equation 2x2+4x-7=0.

As per the questions

It is given that

Discriminant of the quadratic equation 2x2+4x-7=0

As we know if the value of discriminant =0 then value of D=0 and

if the value of discriminant >0 then value of D>0

so, first we have to find D=0 as per the questions.

As we know that the value of D=$b^{2} -4ca$

Here the value of a=2 , b= 4 and c = -7

D=$4^{2}-4*(-7)*2$

D=16+56

D=72

So, the value of discriminant of the quadratic equation is 72.

Hence, the value of discriminant of the quadratic equation is 72 and option 1 is correct.

For such type of questions:

https://brainly.in/question/23734364

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