Question

the discriminant of the quadratic equation 4x²-6x+3=0 is?

Answer 1

Answer:

D=√b²-4ac

a=4,b=-6,c=-3

D=√(-6)²-4×4×-3

D=√36+48

D=√84

D=9.1

Step-by-step explanation:

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Answer 2

Answer: The value of discriminant would be $2\sqrt{3}i$.

Step-by-step explanation:

Since we have given that

$4x^2-6x+3=0$

Here, a= 4

b = -6

c= 3

So, the value of discriminant would be

$D=\sqrt{b^2-4ac}\\\\D=\sqrt{(-6)^2-4\times 4\times 3}\\\\D=\sqrt{36-48}\\\\D=\sqrt{-12}\\\\D=2\sqrt{3}i$

Hence, the value of discriminant would be $2\sqrt{3}i$