Question

The discriminant of the quadratic equation
9x*9x-6x-2=0​

Answer 1

Answer:

Hey buddy here is your answer:-

Step-by-step explanation:

The nature of roots of the given quadratic equation is "real and unequal".

The given quadratic equation:

9x^2-6x-2=09x2−6x−2=0

Here, a = 9, b = - 6 and c = -2

To find, the nature of roots of the given quadratic equation = ?

∴ Discriminant, D =b^{2} -4acb2−4ac

=(-6)^{2} -4(9)(-2)=(−6)2−4(9)(−2)

=36 -36(-2)=36−36(−2)

=36 -(-72)=36−(−72)

= 36 + 72

= 108

∵ D = 108 > 0, the roots are real and unequal.

Hence, the nature of roots of the given quadratic equation is "real and unequal".

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