Question

The discriminant of the quadratic equation (x-3)(x-4)=0

1 point

0

1

-1

2

​

Answer 1

♤ 1

♤ (x-3) x ( x-4) = 0

x^2-4x-3x+12=0

x^2-7x+12=0

dicriminent = ( d)=b^2-4ac

here a=1,b=-7,c=12

then according to the formula

= (-7) 12-4 (1) (12)

=49-48

=1

♤ pls follow me and mark me as brainliest if this helps u pls see ya

Answer 2

Answer:

Ans: D. 2

Step-by-step explanation:

If you sit 2 in the explanation this ans will

(x-3) x (x-4)

=x^2-7x+12

=(2x2)-7x2+12 [:. x=2]

=4-14+12

=16-14

=2 (Ans).