The discriminant of the quadratic equation (x-3)(x-4)=0
1 point
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Answers
Answered by
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♤ 1
♤ (x-3) x ( x-4) = 0
x^2-4x-3x+12=0
x^2-7x+12=0
dicriminent = ( d)=b^2-4ac
here a=1,b=-7,c=12
then according to the formula
= (-7) 12-4 (1) (12)
=49-48
=1
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Answered by
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Answer:
Ans: D. 2
Step-by-step explanation:
If you sit 2 in the explanation this ans will
(x-3) x (x-4)
=x^2-7x+12
=(2x2)-7x2+12 [:. x=2]
=4-14+12
=16-14
=2 (Ans).
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