Question

The discriminant of the quadratic equation (x-3)(x-4)=0 *

Answer 1

Step-by-step explanation:

hope it is helpful to you

Answer 2

Step-by-step explanation:

(x-3)×(x-4)=0

x^2-4x-3x+12=0

x^2-7x+12=0

discriminent (d)= b^2-4ac

here a=1,b=-7,c=12

then according to formula

= (-7)^2-4 (1)(12)

= 49-48

=1