the discriminant of x^2-2x-(r^2-1)=0
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Step-by-step explanation:
D=b^2-4ac_______(1)
as,
a=1,b=-2 and c=(r^2-1)
putting value of a,b and c in eq^n(1)
D=(-2)^2-4(1)(r^2-1)
D=4-4r^2+4
D=8-4r^2
________this is your answer___________
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