Question

the discriminant of x2+x+1=0 is​

Answer 1

Answer:

D=√(b²-4ac) =√(1-4*1*1) =√(-3) =√3 i

Answer 2

Answer:

I hope it helps.............

$x^{2} + x +1 = 0$

a = 1

b = 1

c = 1

$D = b^{2} - 4ac\\\\D = (1)^{2} - 4(1)(1)\\\\D= 1 - 4\\\\D = -3$

since D < 0 thus this equation will have no real roots