Question

the discriminate of the equation 3
$3 {x}^{2} - 2 \sqrt{3x} + 1 = 0is$
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Answer 1

Answer:-

Solution::-----

$3x{}^{2}-2\sqrt{3x}+1=0$

$3x{}^{2}-(\sqrt{3}+\sqrt{3})x+1=0$

$3x{}^{2}-\sqrt{3}x-\sqrt{3}x+1=0$

$\sqrt{3}(\sqrt{3}x-1) +1(\sqrt{3}x-1)=0$

$(\sqrt{3}x+1) (\sqrt{3}x-1)=0$

$So,\sqrt{3}x+1=0$

$\sqrt{3}x=-1$

$x=\frac{-1}\sqrt{3}$

$\sqrt{3}x-1=0$

$\sqrt{3}x=1$

$x=\frac{1}\sqrt{3}$

Hope it's help you