The dispalcement of a particle is proportional to the cube of time. Then magnitude of its acceleration
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The displacement of a body is directly proportional to the cube of the time elapsed,
s∝t
3
s=kt
3
velocity, v=
dt
ds
v=3kt
2
Acceleration, a=
dt
dv
a=6kt
Acceleration of a body is directly proportional to the time,
a∝t
Acceleration of a body incresing with the time.
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what is this ???
Explanation:
l don't understand
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