Question

The displacement and time t for a particle are related
each other as t= 5x+3. What is work done in firsn
seconds of its motion?
a) 6J b) zero c) 4Jd) 2 J
​

Answer 1

Given

t = 5x + 3

differentiating with respect to t

1 = 5dx/dt

again differentiating with respect to t

d^2x/dt^2 = 0

We know that

acceleration of body = d^2x/dt^2

So

acceleration = 0

we also know that

work done = FScos@

since

F = mass *acceleration

F = 0

work done by body= 0*scos@ = 0

Answer 2

Answer:

Here is your answer ll

Hope it helps you