Question

The displacement from mean position of a particle in SHM at root3 by 2 seconds is of the amplitude. Its
time period will be :-​

Answer 1

Explanation:

Given The displacement from mean position of a particle in SHM at 3 secs is root 3 by 2 of the amplitude. Its  time period will be

• The position of particle from mean position from x = 0 after a time t is
• x = a sin ωt
• √3 / 2 a = a sin ωt
• Sin ωt = √3 / 2  
• Sin ωt = sin π/3
• So ωt = π/3
• So 2π/t x 3 = π/3
• 6/t = 1/3

Or t = 18 secs.

So time period will be 18 secs.

Answer 2

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