The displacement (in metre) of a particle moving along x-axis is given by x = 18t + 5t2 : calculate (i) the instantaneous velocity at t=2 sec (ii) average velocity between t=2 sec and t=3sec. (iii) instantaneous llcceleration.
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given X=18t+5t2
( I) instantaneous vlocity =dx/dt
d/dt(18t+5t2)=18+10t
at t=2:18+10(2)=38
II)
( I) instantaneous vlocity =dx/dt
d/dt(18t+5t2)=18+10t
at t=2:18+10(2)=38
II)
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