Question

The
displacement of a body
body is represented as
X = 3t^4 +4t^3+t^2. Find its velocity and aceleration at the time, t = 2 s.​

Answer 1

Answer:

Given displacement x=5+3t+2t

2

Differentiating the above equation with respect to time t we get velocity of the body

v=

dt

dx

=3+4t

Now again differentiating the velocity with respect to time we get acceleration

a=

dt

dv

=4

Explanation:

use this formula