Question

the displacement of a body in t sec is given by x=3+2t+1/2t2 in meter its acceleration

Answer 1

$x=3+2t+1/2t^{2}\\v=dx/dt=0+2+(1/2)(-2)t^{-3}\\\d(x^n)/dx=nx^{n-1}\\a=dv/dt=dx^2/dt^2=0+0+(-1)(-3)t^{-4}\\\a=(3/t^{4})m/s^2$

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