Question

the displacement of a body of mass 4kg as function of time is given by x(t)=t^2+10. the increase in itsKinetic energy one second after the start of motion is how much????

Answer 1

Explanation:

x(t)=t^2+10

dx/dt=2t

v=2t

at t=0

v=0

K.Ei=1/2×4×0

=0j

at t =1 sec

v=2 m/s

K.Ef=1/2×4×4

=4j

KEf-KEi=4j

the increase in kinetic energy is 4 jouls