Question

The displacement of a particle along x- axis is given by x- 3 plus 8t plus 7t square . Obtain its velocity and acceleration at t is 2 seconds

Answer 1

Hello here is the answer below,

As per the question,

x = 3 + 8t + 7t^2

Now if you differentiate it, you will get,

v = 8 + 14t ...... (i)

And again differentiating,

a = 14 .......... (ii)

So on putting t = 2 in eq (i) we get,

v = 36m/s

And as a is independent of t so it will remain constant.

Hope this will help you.

Answer 2

this problem can be solved using differentiation