Question

the displacement of a particle executing SHM is given by
x=0.01 sin(100 pi t +0.05).
its time period is what?

Answer 1

Time period is 0.02 s.

Given equation:

$x=0.01 \sin (100 \pi t+0.05)$ for the displacement of the particle in Simple Harmonic Motion.  

To calculate the time period T, the value of angular velocity can be taken from the given equation.

In SHM, displacement x is given by, $x=A \sin (\omega t+\phi)$

The quantity $(\omega t+\phi)$ is called phase. Comparing the given equation and displacement equation

$\begin{aligned} \omega t &=100 \pi t \\ \omega &=100 \pi \\ \omega &=\frac{2 \pi}{T} \\ \frac{2 \pi}{T} &=100 \pi \\ \frac{2}{T} &=100 \\ T &=0.02 s \end{aligned}$

Answer 2

Answer:

time period is 0.02 s

Explanation:

hope it helped