Question

The displacement of a particle executing shm is given by x=0.01 sin 100 π (t+0.05). the time period?

Answer 1

Explanation:

Given:x=0.01sin100π(t+0.05)=0.01sin(100πt+5)

S.H.M equation is x=Asin(ωt+ϕ)

Comparing the above equations, we get

A=0.01, ωt=100πt

⇒ω=100π

⇒

T

2π

=100π

⇒

T

1

=50

⇒T=

50

1

×

2

2

=

100

2

=0.02 secs

I hope this answer is useful.