Question

The displacement of a particle in x direction is given by x is equal to 9-5t+4t^2 find the velocity when time is 0

Answer 1

Answer:

$x = 9 - 5t + 4 {t}^{2} \\ \frac{dx}{dt} = \frac{d}{dt} (9 - 5t + 4 {t}^{2} ) \\ = - 5 + 8t \\ \frac{dx}{dt}( t = 0) = - 5 \\ hence \: v = - 5$

Answer 2

Answer:

Hey mate your answer is given below