Question

The displacement of a particle is given by S equal 2t*2t-3t find acceleration at t. Equal 2sec

Answer 1

Answer:

Position of the particle   x=2t2−t3

Velocity   v=dtdx=4t−3t2

Acceleration   a=dtdv=4−6t

So,    a( at t=2 s)=4−6×2=−8 m/s2

Since, acceleration is depending on the time. SO, acceleration is not constant.