The displacement of a particle is represented by s=2t^3+7t^2+5t+8 the acceleration of particle at t=1 second is
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Answer:
Explanation:
just differentiate it two times and put the value of t
ds/dt=6t^2+14t+5=v
dv/dt=a
a=12t+14=12+14=26ms^-2
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