Question

The displacement of a particle is x=a0 + a1t^2/2 + a2t^2/3.What is teh acceleration?

Answer 1

Answer:

(6a1 + 4a2)/6

Explanation:

We Know acceleration is equal to dv/dt

We Know v = dx/dt

So,

a = d²x/dt²

We Have Given

$x = a_{0} + (a_{1}t^{2})/2 (a_{2}t^{2})/3$

So After Double Differentiating the equation, We Get,

$a = \frac{d^{2}x}{dt^{2}} = (6a_{1}t^{2} + 4a_{2}t^{2})/6$