Question

the displacement of a particle moving alone a straight line is given by s=3t³+2t²-10t+9​

Answer 1

Answer:

Explanation:

et the velocity of the particles be V.

Velocity(V) = ds/dt

∴ V= ds/dt = 3t²-12t+3

Hence,the acceleration of the particles will be :

a = dv/dt

a = 6t-12

But, a = 0

It follows that :

6t-12=0

∴ 6t = 12

∴ t = 2s

Therefore,

V = 3(2)² - 12(2) + 3,when t= 2s

V = 12 - 24 + 3

V = -9m/s

V = 9m/s

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