The displacement of a particle moving along x axis given by x=18t+6t2 calculate the instantaneous velocity at t=5 sec
Answers
Answered by
0
Answer:
on differentiation of X= 18t+6t2 , we get 18+6 t , now putting the value of t , we get 18+6×5 = 48 m/s
Answered by
1
Answer :
Displacement = x = 18t + 6t².
Differentiating x :
⇒ v = dx/dt
⇒ 18 + 6*2t
⇒ 18 + 12t
Now, Instantaneous velocity at 2 seconds :
⇒ 18 + 12*5
⇒ 18 + 60
⇒ 78 m/s
Hence, Instantaneous velocity at time of 5 seconds = 78 m/s.
Some Additional Information -
- Distance is the length of the total path travelled by a body.
- Displacement is the shortest distance between the initial position and the final position of the body.
- Speed is the Distance travelled per unit time.
- Velocity is the Displacement per unit time.
Similar questions