Question

The displacement of a particle moving along x axis is given by x=18t+5t^2 m. Find the av velocitybetween t=2s and t=3s

Answer 1

Answer:

17.2 m/s

Explanation:

here x= 18t + 5t^2

by differentiation,

dv/dt=v= 18+ 10t

put t1 = 2,

18 + 10×2= 38m/s=v1

put t2=3,

18+ 10×3= 48m/s=v2

now,

average velocity= v1+v2/t1+t2

=38+48/3+2

= 17.2m/s