Physics, asked by shivgujjar12, 4 months ago

The displacement of a particle moving along x axis is given by x= 18 t, its
velocity and acceleration at t=2s
(a) 36m/s, 18m/s2
(b) 18m/s,Om/s2
(c) Om/s,18m/s2
(d) 9m/s,Om/s?

Answers

Answered by Ekaro
6

Answer :

The displacement of a particle moving along x axis is given by x = 18t

We have to find velocity and acceleration of the particle.

Given that : x = 18t

In order to find velocity of the particle we have to differentiate the given displacement equation.

➝ v = dx/dt

➝ v = d(18t) / dt

➝ v = 18 m/s

Here we can see that, velocity of particle doesn't depend on time. It means body is moving at a constant velocity which is equal to 18m/s.

In order to find acceleration of the particle we have to again differentiate velocity equation.

➝ a = dv/dt

➝ a = d(18)/dt

➝ a = 0 m/s²

Body doesn't have acceleration.

(B) is the correct answer!

Answered by Anonymous
4

⛄ \fbox{ \: given}

displacement= 18 t along X axis

time = 2 second

____________________________________

⛄ \fbox{to \: find}

1. velocity

1. velocity2. acceleration

_______________________________

 \fbox{solution}

In order to find the velocity we have to differentiate x= 18t.

d(v) =  \frac{d(x)}{dt}

dv =  \frac{18t}{dt}  = 18 \frac{m}{second}

♠️Velocity of the particle here is independent of time . This means the particle is moving with a constant velocity.

To find acceleration we have to again differentiate the velocity now.

d(a) =  \frac{d(v)}{dt}

Differentiation of a constant is zero

d(a) =  \frac{18}{dt}  = 0

Therefore acceleration is 0.

 \fbox{therefore option B is correct.}

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