the displacement of a particle moving along x axis is given by x=18t+5t^2. calculate its instantaneousvelocity at t=2 secand it's instantaneous acceleration
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x=18t + 5t^2
v = dx/dt
=18 +10t = 18 + 10 ×2 =38 m/s
dv/dt=10 m/s^2
simple differentiation.
v = dx/dt
=18 +10t = 18 + 10 ×2 =38 m/s
dv/dt=10 m/s^2
simple differentiation.
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