Question

The displacement of a particle moving along X axis is given by X=a+bt+ct^2. Find acceleration​

Answer 1

We know,

$displacement \: = ut + \frac{1}{2} a {t}^{2}$

So, we can see in the above relation that t is the time while a should be equal to 0 as there is no place for it. Hence, our relation becomes:

$\frac{1}{2} a = c \\ = > a = 2c$

HOPE THIS COULD HELP!!!

Answer 2

The acceleration of the particle will be 2c.

Given,

The displacement of a particle moving along the x-axis is given by x = a+bt+ct².

To Find,

The acceleration of the particle.

Solution,

The velocity of a particle is calculated as

v = dx/dt

Now,

v = d(a+bt+ct²)/dt

v = 0+b+2ct

v = b+2ct

Now,

The acceleration of a particle is given as

a = dv/dt

a = d(b+2ct)/dt

a = 0+2c

a = 2c

Hence, the acceleration of the particle will be 2c.

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