Question

The displacement of a particle, moving in a straight line, is given by s = 2t2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is
1) 2 m/s2
2) 4 m/s2
3) 6 m/s2
4) 8 m/s2​

Answer 1

SOLUTION :

Displacement of the particles ,

s = 2t² + 2t + 4

differentiate both side with respect to dt , we get

$\: \: \: \: \: \: \: \: \: \frac{ds}{dt } = \frac{d}{dt} (2 {t}^{2} + 2t + 4)$

$\: \: \: \: \: \: \: v = 4t + 2$

again, differentiate both side with respect dt , we get

$\: \: \: \: \: \: \: \: \frac{dv}{dt} = \frac{d}{dt} (4t + 2)$

$\: \: \: \: \: \: \: \: a = 4m {s}^{ - 2}$

Answer 2

Answer:

dd

Explanation: