Physics, asked by pratikkirankhune33, 30 days ago

The Displacement of a Particle performing linear S.H.M is x=8sin(5 pi t+(pi)/(6)) where time is in second displacement is in meter calculate displacement velocity acceleration at t=2sec help me.​

Answers

Answered by sheetalporwal6981
0

Explanation:

y=0.3sin20π(t+0.05)

y=0.3sin(20πt+π)

Comparing the given equation with the standard equation y=Asin(ωt+ϕ)

By comparison

ω=20π

⇒phi=π

⇒A=0.3

Thus, amplitude and initial phase is known

Amplitude (A)=0.3m

Initial phase (ϕ)=π

Then, for calculating time period

T=

ω

=

20π

=

10

1

s=0.1s

⇒ Time period (T)=0.1s

Also for initial displacement t=0

⇒y=0.3sin(π)=0

Thus, initial displacement =0.

Attachments:
Similar questions