The Displacement of a Particle performing linear S.H.M is x=8sin(5 pi t+(pi)/(6)) where time is in second displacement is in meter calculate displacement velocity acceleration at t=2sec help me.
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Explanation:
y=0.3sin20π(t+0.05)
y=0.3sin(20πt+π)
Comparing the given equation with the standard equation y=Asin(ωt+ϕ)
By comparison
ω=20π
⇒phi=π
⇒A=0.3
Thus, amplitude and initial phase is known
Amplitude (A)=0.3m
Initial phase (ϕ)=π
Then, for calculating time period
T=
ω
2π
=
20π
2π
=
10
1
s=0.1s
⇒ Time period (T)=0.1s
Also for initial displacement t=0
⇒y=0.3sin(π)=0
Thus, initial displacement =0.
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