Question

the displacement of a particle started from origin is represented by following equation s = 3t^3 + 7 t^2, where s is in metre and t in second. the acceleration of particle at t = 1 s ( in m s^-2) is. a) 9. b) 18 c) 32. d) 37​

Answer 1

Answer:

(c) $32 ms^{-2}$

Explanation:

Double differential of displacement gives acceleration.

$s=3t^{3} +7t^{2}$

$\frac{ds}{dt} = 9t^{2} +14t$

$\frac{d^{2} s}{dt^{2} } = 18t+14$

at $t=1$, $a= 14+18=32ms^{-2}$

FYI:

$\frac{d^{2} s}{dt^{2} } = a$

Kudos!